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- <template>
- <div id="app">
- <Header></Header>
- <WorkMaster></WorkMaster>
- <div class="wrap ov bodyContent">
- <RecomLeft></RecomLeft>
- <div class="main fr">
- <h4 ><a href="/">首页</a> > 在线检测</h4>
- <div class="content ov bgf pad20">
- <!--<Screen></Screen>-->
- <!--<ScreenSort></ScreenSort>-->
- <h3 class="tc" style="font-size: 20px; background: #eee;padding:10px 0;margin:10px 0;">人教五上第五单元_列方程解决实际问题</h3>
- <div class="ov AnchorBox">
- <ul class="checkList checkList2 fl">
- <!-- <li v-for="(item,index) in list" :id="'sub'+(index+1)">
- <h3>
- 第{{index+1}}题:
- <span :class="'dif dif'+item.dif">
- <b v-if="item.dif==1">容易</b>
- <b v-if="item.dif==2">较易</b>
- <b v-if="item.dif==3">一般</b>
- <b v-if="item.dif==4">较难</b>
- <b v-if="item.dif==5">困难</b>
- </span>
- <span class="type">{{item.type}}</span>
- {{item.title}}
- </h3>
- <RadioGroup vertical >
- <Radio v-for="(items,indexs) in item.options" :label="indexs">
- <span>{{items.option}} :{{items.txt}}</span>
- </Radio>
- </RadioGroup>
- <!–<ol class="answer">–>
- <!–<li>【参考答案】:{{item.answer}}</li>–>
- <!–<li>【答题解析】:{{item.explain}}</li>–>
- <!–</ol>–>
- </li> -->
- <li v-for="(item,index) in list2" :id="'sub'+(index+1)">
- <h3>
- 第{{index+1}}题:
- <!--<span class="dif dif1"><b>容易</b></span>-->
- <span :class="'dif dif'+item.dif">
- <b v-if="item.dif==1">容易</b>
- <b v-if="item.dif==2">较易</b>
- <b v-if="item.dif==3">一般</b>
- <b v-if="item.dif==4">较难</b>
- <b v-if="item.dif==5">困难</b>
- </span>
- <span class="type" v-if="item.Type=='Single'">单选</span>
- <span class="type" v-if="item.Type=='Multiple'">多选</span>
- <span class="type" v-if="item.Type=='Complete'">填空</span>
- <span class="type" v-if="item.Type=='Subjective'">主观题</span>
- <i v-html="item.Question"></i>
- </h3>
- <CheckboxGroup v-model="fruit" v-if="item.Type=='Multiple'">
- <Checkbox v-for="(items,indexs) in item.Option" >
- <span v-html="items.Code+' :'+items.Value"></span>
- </Checkbox>
- </CheckboxGroup>
- <RadioGroup vertical v-else>
- <Radio v-for="(items,indexs) in item.Option" :label="indexs">
- <span v-html="items.Code+' :'+items.Value"></span>
- </Radio>
- </RadioGroup>
- <!--<ol class="answer">-->
- <!--<li>【参考答案】:{{item.answer}}</li>-->
- <!--<li>【答题解析】:{{item.explain}}</li>-->
- <!--</ol>-->
- </li>
- </ul>
- <Anchor show-ink style="display: block;width:28%;float:right;">
- <div class="numCard" style="width: 100%">
- <p><Icon type="md-time" size="24" /> 剩余时间 <b>14:15</b></p>
- <div class="answerCard">
- <h5>答题卡</h5>
- <div class="num">
- <div class="ov" >
- <AnchorLink v-for="(item,index) in list2" :href="'#sub'+(index+1)" :title="index+1" />
- </div>
- <!--<ol>-->
- <!--<li class="active">1</li>-->
- <!--<li>2</li>-->
- <!--<li>3</li>-->
- <!--<li>4</li>-->
- <!--<li>5</li>-->
- <!--<li>6</li>-->
- <!--</ol>-->
- <p><a href="/report"><Button type="success" long>交卷并查看检测报告</Button></a></p>
- </div>
- </div>
- </div>
- </Anchor>
- </div>
- <!--<Page :total="100" size="small" show-total class="fr" />-->
- </div>
- </div>
- </div>
- <Footer></Footer>
- </div>
- </template>
- <script>
- import Header from '@/common/header.vue'
- import WorkMaster from '@/common/workMaster.vue'
- import WorkLeft from '@/common/workLeft.vue'
- import RecomLeft from '@/common/recomLeft.vue'
- import Screen from '@/common/screen.vue'
- import Textbook from '@/common/textbook.vue'
- import ScreenSort from '@/common/screenSort.vue'
- import Footer from '@/common/footer.vue'
- import ScoreList from '@/components/scoreList.vue'
- export default {
- components: {
- Header,
- WorkMaster,
- WorkLeft,
- RecomLeft,
- Screen,
- Textbook,
- ScreenSort,
- Footer,
- ScoreList
- },
- data ( ) {
- return {
- valueText: 5,
- modal1: false,
- formItem: {
- select: 'sel1',
- select2: 'sel2',
- input: '',
- textarea: '',
- },
- list:[
- {
- id:'1',
- type:'单选',
- dif:'1',
- title:'1928年12月,在东北宣布"服从南京国民政府,改易旗帜"的是 ( )',
- options:[
- {option:'A',txt:'孙传芳'},
- {option:'B',txt:'吴佩孚'},
- {option:'C',txt:'张作霖'},
- {option:'D',txt:'张学良'}
- ],
- answer:'A',
- explain:'题考查的是标志着近代以来中国争取民族独立和人民解放的历史任务基本完成的事件。人民民主专政的新中国的创建,标志着近代以来中国面临的争取民族独立、人民解放这个历史任务的基本完成,这就为中国人民集中力量进行建设,以实现国家的繁荣富强和人民的共同富裕,创造了前提,开辟了道路。'
- },
- {
- id:'1',
- type:'单选',
- dif:'1',
- title:'1928年12月,在东北宣布"服从南京国民政府,改易旗帜"的是 ( )',
- options:[
- {option:'A',txt:'孙传芳'},
- {option:'B',txt:'吴佩孚'},
- {option:'C',txt:'张作霖'},
- {option:'D',txt:'张学良'}
- ],
- answer:'A',
- explain:'题考查的是标志着近代以来中国争取民族独立和人民解放的历史任务基本完成的事件。人民民主专政的新中国的创建,标志着近代以来中国面临的争取民族独立、人民解放这个历史任务的基本完成,这就为中国人民集中力量进行建设,以实现国家的繁荣富强和人民的共同富裕,创造了前提,开辟了道路。'
- },
- {
- id:'1',
- type:'单选',
- dif:'2',
- title:'1928年12月,在东北宣布"服从南京国民政府,改易旗帜"的是 ( )',
- options:[
- {option:'A',txt:'孙传芳'},
- {option:'B',txt:'吴佩孚'},
- {option:'C',txt:'张作霖'},
- {option:'D',txt:'张学良'}
- ],
- answer:'A',
- explain:'题考查的是标志着近代以来中国争取民族独立和人民解放的历史任务基本完成的事件。人民民主专政的新中国的创建,标志着近代以来中国面临的争取民族独立、人民解放这个历史任务的基本完成,这就为中国人民集中力量进行建设,以实现国家的繁荣富强和人民的共同富裕,创造了前提,开辟了道路。'
- },
- {
- id:'1',
- type:'单选',
- dif:'3',
- title:'1928年12月,在东北宣布"服从南京国民政府,改易旗帜"的是 ( )',
- options:[
- {option:'A',txt:'孙传芳'},
- {option:'B',txt:'吴佩孚'},
- {option:'C',txt:'张作霖'},
- {option:'D',txt:'张学良'}
- ],
- answer:'A',
- explain:'题考查的是标志着近代以来中国争取民族独立和人民解放的历史任务基本完成的事件。人民民主专政的新中国的创建,标志着近代以来中国面临的争取民族独立、人民解放这个历史任务的基本完成,这就为中国人民集中力量进行建设,以实现国家的繁荣富强和人民的共同富裕,创造了前提,开辟了道路。'
- },
- {
- id:'1',
- type:'单选',
- dif:'4',
- title:'1928年12月,在东北宣布"服从南京国民政府,改易旗帜"的是 ( )',
- options:[
- {option:'A',txt:'孙传芳'},
- {option:'B',txt:'吴佩孚'},
- {option:'C',txt:'张作霖'},
- {option:'D',txt:'张学良'}
- ],
- answer:'A',
- explain:'题考查的是标志着近代以来中国争取民族独立和人民解放的历史任务基本完成的事件。人民民主专政的新中国的创建,标志着近代以来中国面临的争取民族独立、人民解放这个历史任务的基本完成,这就为中国人民集中力量进行建设,以实现国家的繁荣富强和人民的共同富裕,创造了前提,开辟了道路。'
- },
- {
- id:'1',
- type:'单选',
- dif:'5',
- title:'1928年12月,在东北宣布"服从南京国民政府,改易旗帜"的是 ( )',
- options:[
- {option:'A',txt:'孙传芳'},
- {option:'B',txt:'吴佩孚'},
- {option:'C',txt:'张作霖'},
- {option:'D',txt:'张学良'}
- ],
- answer:'A',
- explain:'题考查的是标志着近代以来中国争取民族独立和人民解放的历史任务基本完成的事件。人民民主专政的新中国的创建,标志着近代以来中国面临的争取民族独立、人民解放这个历史任务的基本完成,这就为中国人民集中力量进行建设,以实现国家的繁荣富强和人民的共同富裕,创造了前提,开辟了道路。'
- },
- ],
- list2:
- [
- {
- "$id": "1",
- "Question": "若代数式在实数范围内有意义,则x的取值范为是()</p><p class=\"p4\">",
- "dif":"1",
- "Option": [{
- "$id": "2",
- "Code": "A",
- "Value": "x≥-2 "
- }, {
- "$id": "3",
- "Code": "B",
- "Value": "x>-2 "
- }, {
- "$id": "4",
- "Code": "C",
- "Value": "x≥2 "
- }, {
- "$id": "5",
- "Code": "D",
- "Value": "x≤2</p><p class=\"p3\">"
- }],
- "Answer": ["C"],
- "Explain": "</p><p class=\"p5\">二次根式有意义,被开方数是非负数,故x-2≥0,x大于等于2.</p><p class=\"p3\">备考指导:代数式有意义的条件,一般从三个方面考虑:</p><p class=\"p3\">(1)当表达式是整式时,可取全体实数;</p><p class=\"p3\">(2)当表达式是分式时,考虑分式的分母不能为0;</p><p class=\"p3\">(3)当表达式是二次根式时,被开方数非负.</p><p class=\"p3\">",
- "Type": "Single"
- },
- {
- "$id": "6",
- "Question": "下列计算正确的是()</p><p class=\"p3\">",
- "dif":"1",
- "Option": [{
- "$id": "7",
- "Code": "A",
- "Value": "2x2-4x2=-2 </p><p class=\"p3\">"
- }, {
- "$id": "8",
- "Code": "B",
- "Value": "3x+x=3x2 </p><p class=\"p6\">"
- }, {
- "$id": "9",
- "Code": "C",
- "Value": "3x·x=<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/0.png\" style=\"width:0.29166666in;height:0.22916667in;vertical-align:text-bottom;\"> </p><p class=\"p3\">"
- }, {
- "$id": "10",
- "Code": "D",
- "Value": "4x6÷2x2=2x3</p><p class=\"p3\">"
- }],
- "Answer": ["C"],
- "Explain": "</p><p class=\"p7\">本题考查整式的基本运算,对选项进行逐项分析</p><table class=\"t1\"><tbody><tr class=\"r1\"><td class=\"td1\"><p class=\"p8\">选项</p></td><td class=\"td2\"><p class=\"p3\">逐项分析</p></td><td class=\"td3\"><p class=\"p3\">正误</p></td></tr><tr class=\"r1\"><td class=\"td1\"><p class=\"p7\">A</p></td><td class=\"td2\"><p class=\"p7\">2x2-4x2=-2x2≠-2</p></td><td class=\"td3\"><p class=\"p7\">×</p></td></tr><tr class=\"r1\"><td class=\"td1\"><p class=\"p7\">B</p></td><td class=\"td2\"><p class=\"p7\">3x+x=4x≠3 x2</p></td><td class=\"td3\"><p class=\"p7\">×</p></td></tr><tr class=\"r1\"><td class=\"td1\"><p class=\"p7\">C</p></td><td class=\"td2\"><p class=\"p7\">3x·x=3 x2</p></td><td class=\"td3\"><p class=\"p7\">√</p></td></tr><tr class=\"r1\"><td class=\"td1\"><p class=\"p7\">D</p></td><td class=\"td2\"><p class=\"p7\">4x6÷2x2=2x4≠2x3</p></td><td class=\"td3\"><p class=\"p7\">×</p></td></tr></tbody></table><p class=\"p7\">备考指导:整式加减,实质是合并同类项,只把系数相加减,字母及字母的指数不变;整式乘法,系数相乘作为积的系数,相同的字母按照同底数幂的乘法法则相乘,单独的字母(式)作为积的一个因式;整式相除,系数相除作为商的系数,相同的字母按照同底数幂的除法法则相除,被除式中单独的字母(式)作为积的一个因式.</p><p class=\"p3\">",
- "Type": "Single"
- },
- {
- "$id": "11",
- "Question": "如图,在直角坐标系中,有两点A(6,3)、B(6,0).以原点O为位似中心,相似比为<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/477.png\" style=\"width:0.13541667in;height:0.38472223in;vertical-align:text-bottom;\">,在第一象限内把线段AB缩小后得到线段CD,则点C的坐标为()</p><p class=\"p9\"><img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/690.png\" style=\"width:1.7395834in;height:1.2395834in;vertical-align:text-bottom;\"></p><p class=\"p7\">",
- "dif":"2",
- "Option": [{
- "$id": "12",
- "Code": "A",
- "Value": "(2,1) </p><p class=\"p7\">"
- }, {
- "$id": "13",
- "Code": "B",
- "Value": "(2,0) </p><p class=\"p7\">"
- }, {
- "$id": "14",
- "Code": "C",
- "Value": "(3,3) </p><p class=\"p7\">"
- }, {
- "$id": "15",
- "Code": "D",
- "Value": "(3,1)<a name=\"_GoBack\"></a><a name=\"_GoBack\"></a></p><p class=\"p3\">"
- }],
- "Answer": ["A"],
- "Explain": "</p><p class=\"p7\">∵线段CD和线段AB关于原点位似,∴△ODC∽△OBA,∴<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/10fd.png\" style=\"width:1.0097222in;height:0.42708334in;vertical-align:text-bottom;\">,即<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/137e.png\" style=\"width:1.0097222in;height:0.42708334in;vertical-align:text-bottom;\">,∴CD=1,OD=2,∴C(2,1).</p><p class=\"p7\">一题多解—最优解:设C(x,y),∵线段CD和线段AB关于原点位似,∴<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/1606.png\" style=\"width:0.71805555in;height:0.42708334in;vertical-align:text-bottom;\">,∴x=2,y=1,∴C(2,1).</p><p class=\"p7\">备考指导:每对对应点的连线所在的直线都相交于一点的相似图形叫做位似图形.位似图形对应点到位似中心的距离比等于位似比(相似比);在平面直角坐标系中,如果位似图形是以原点为位似中心,那么位似图形对应点的坐标比等于相似比.</p><p class=\"p3\">",
- "Type": "Single"
- },
- {
- "$id": "16",
- "Question": "在反比例函数<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/188b.png\" style=\"width:0.63472223in;height:0.38541666in;vertical-align:text-bottom;\">图象上有两点A(x1,y1)、B(x2,y2),x1<0<y1,y1<y2,则m的取值范围是()</p><p class=\"p7\">",
- "dif":"3",
- "Option": [{
- "$id": "17",
- "Code": "A",
- "Value": "m><img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/1b05.png\" style=\"width:0.13541667in;height:0.38472223in;vertical-align:text-bottom;\"> "
- }, {
- "$id": "18",
- "Code": "B",
- "Value": "m<<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/1d1f.png\" style=\"width:0.13541667in;height:0.38472223in;vertical-align:text-bottom;\"> "
- }, {
- "$id": "19",
- "Code": "C",
- "Value": "m≥<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/1f39.png\" style=\"width:0.13541667in;height:0.38472223in;vertical-align:text-bottom;\"> "
- }, {
- "$id": "20",
- "Code": "D",
- "Value": "m≤<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/2153.png\" style=\"width:0.13541667in;height:0.38472223in;vertical-align:text-bottom;\"></p><p class=\"p3\">"
- }],
- "Answer": ["D"],
- "Explain": "</p><p class=\"p10\">x1<0<x2时,y1<y2,说明反比例函数图像位于一三象限,故1-3m>0,所以m≤<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/236f.png\" style=\"width:0.15555556in;height:0.42708334in;vertical-align:text-bottom;\">.</p><p class=\"p7\">易错警示:对于x1<0<x2时,y1<y2,部分同学容易误认为y随x增大而增大,故错误得出1-3m<0.考虑反比例函数增减性要在同一个分支上,x1<0<x2说明点A、B不在同一个分支上,故不能利用增减性来解答.备考指导:①反比例函数<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/258f.png\" style=\"width:0.6145833in;height:0.42708334in;vertical-align:text-bottom;\">为常数,且<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/27f6.png\" style=\"width:0.45833334in;height:0.21805556in;vertical-align:text-bottom;\">的图像是双曲线,当<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/2a31.png\" style=\"width:0.375in;height:0.19791667in;vertical-align:text-bottom;\">时,双曲线的两支分别位于第一、第三象限,在每个象限内y值随x值的增大而减小;当<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/2c65.png\" style=\"width:0.125in;height:0.23958333in;vertical-align:text-bottom;\"><img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/2de9.png\" style=\"width:0.375in;height:0.19791667in;vertical-align:text-bottom;\">时,双曲线的两支分别位于第二、第四象限,在每个象限内y值随x值的增大而增大.②两个点若在双曲线同一分支上,则两点纵坐标符号相同,横坐标符号相同,两个点若不在双曲线同一分支上,则两点纵坐标符号相反,横坐标符号相反.</p><p class=\"p3\">",
- "Type": "Single"
- },
- {
- "$id": "21",
- "Question": "如图,△ABC、△EFG均是边长为2的等边三角形,点D是边BC、EF的中点,直线AG、FC相交于点M.当△EFG绕点D旋转时,线段BM长的最小值是()</p><p class=\"p9\"><img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/301d.png\" style=\"width:1.875in;height:1.8541666in;vertical-align:text-bottom;\"></p><p class=\"p7\">",
- "dif":"3",
- "Option": [{
- "$id": "22",
- "Code": "A",
- "Value": "<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/5328.png\" style=\"width:0.41597223in;height:0.23958333in;vertical-align:text-bottom;\"> </p><p class=\"p7\">"
- }, {
- "$id": "23",
- "Code": "B",
- "Value": "<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/5594.png\" style=\"width:0.38472223in;height:0.23958333in;vertical-align:text-bottom;\"> </p><p class=\"p7\">"
- }, {
- "$id": "24",
- "Code": "C",
- "Value": "<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/5805.png\" style=\"width:0.23958333in;height:0.21805556in;vertical-align:text-bottom;\"> </p><p class=\"p7\">"
- }, {
- "$id": "25",
- "Code": "D",
- "Value": "<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/5a3e.png\" style=\"width:0.38472223in;height:0.23958333in;vertical-align:text-bottom;\"></p><p class=\"p3\">"
- }],
- "Answer": ["D"],
- "Explain": "</p><p class=\"p11\">先考虑让△EFG和△BCA重合,然后把△EFG绕点D顺时针旋转,连结AG、DG,根据旋转角相等,旋转前后的对应线段相等,容易发现∠ADG=∠FDC,DA=DG,DF=DC,故∠DFC=∠DCF=∠DAG=∠DGA.又根据等腰三角形的“三线合一”可知∠FDG=90°,所以∠DFG+∠DGF=90°,即∠DFC+∠CFG+∠DGF=90°. 所以∠AMC=∠MGF+∠CFG=∠AGD+∠DGF+∠CFG=∠DFC +∠DGF+∠CFG =90°.故点M始终在以AC为直径的圆上,作出该圆,设圆心为O,连结BO与⊙O相交于点P,线段BP的长即为线段BM长的最小值.BP=AO-OP=<img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/5caf.png\" style=\"width:0.25in;height:0.25in;vertical-align:text-bottom;\">-1,故选D.</p><p class=\"p6\">【难点突破】本题发现点M始终在以AC为直径的圆上是解题的重要突破口.考虑让△EFG和△BCA重合,然后把△EFG绕点D顺时针旋转,借助旋转的性质找出解题思路是分析有关旋转问题的重要方法.</p><p class=\"p12\"></p><p class=\"p13\"><img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/5fe7.png\" style=\"width:2.0729167in;height:1.9270834in;vertical-align:text-bottom;\"></p><p class=\"p3\">",
- "Type": "Single"
- },
- {
- "$id": "26",
- "Question": "在实数-3、0、5、3中,正数有是()</p><p class=\"p7\">",
- "dif":"3",
- "Option": [{
- "$id": "27",
- "Code": "A",
- "Value": "3 "
- }, {
- "$id": "28",
- "Code": "B",
- "Value": "-3 "
- }, {
- "$id": "29",
- "Code": "C",
- "Value": "5 "
- }, {
- "$id": "30",
- "Code": "D",
- "Value": "0</p><p class=\"p3\">"
- }],
- "Answer": ["A", "C"],
- "Explain": "</p><p class=\"p14\">无</p><p class=\"p6\">",
- "Type": "Multiple"
- },
- {
- "$id": "31",
- "Question": "若代数式在实数范围内有意义,则x的取值范为是()</p><p class=\"p7\">",
- "dif":"1",
- "Option": [{
- "$id": "32",
- "Code": "A",
- "Value": "x≥-2 "
- }, {
- "$id": "33",
- "Code": "B",
- "Value": "x>-2 "
- }, {
- "$id": "34",
- "Code": "C",
- "Value": "x≥2 "
- }, {
- "$id": "35",
- "Code": "D",
- "Value": "x≥4</p><p class=\"p3\">"
- }],
- "Answer": ["C", "D"],
- "Explain": "</p><p class=\"p7\">备考指导:代数式有意义的条件,一般从三个方面考虑:</p><p class=\"p7\">(1)当表达式是整式时,可取全体实数;</p><p class=\"p7\">(2)当表达式是分式时,考虑分式的分母不能为0;</p><p class=\"p7\">(3)当表达式是二次根式时,被开方数非负.</p><p class=\"p3\">",
- "Type": "Multiple"
- },
- {
- "$id": "36",
- "Question": "下面的折线图描述了某地某日的气温变化情况,根据图中信息,下列说法正确的是()</p><p class=\"p15\"><img src=\"https://teammodelstorage.blob.core.chinacloudapi.cn/teammodelosevaluation/20190521/1130766061831061504/static/7c32.png\" style=\"width:5.146528in;height:2.0625in;vertical-align:text-bottom;\"></p><p class=\"p7\">",
- "dif":"4",
- "Option": [{
- "$id": "37",
- "Code": "A",
- "Value": "4:00气温最低 </p><p class=\"p7\">"
- }, {
- "$id": "38",
- "Code": "B",
- "Value": "6:00气温为24℃ </p><p class=\"p7\">"
- }, {
- "$id": "39",
- "Code": "C",
- "Value": "14:00气温最高 </p><p class=\"p7\">"
- }, {
- "$id": "40",
- "Code": "D",
- "Value": "气温是30℃的为16:00</p><p class=\"p3\">"
- }],
- "Answer": ["A", "B", "C"],
- "Explain": "</p><p class=\"p7\">从图像可以看出最低点对应点时间是4:00时,即4:00时温度最低,故A正确;6:00对应的温度为24℃,故B正确;图形最高点对应14:00时,即14:00时温度最高,故C正确;气温是30℃时对应两个时间12:00时和16时,故D错误.</p><p class=\"p7\">备考指导:解决此类问题的时,要注意结合函数图像和题意弄清横轴、纵轴的实际意义,以及图像上特殊点的实际意义.此类问题一般的解答方式是根据一个坐标找到对应图像上的点,再确定这个点的另一个坐标;图像的最高(低)点对应函数最大(小)值.</p><p class=\"p3\">",
- "Type": "Multiple"
- },
- {
- "$id": "41",
- "Question": "在实数-3、0、5、3中,最小的实数是-3()</p><p class=\"p7\">",
- "dif":"3",
- "Option": [{
- "$id": "42",
- "Code": "A",
- "Value": "对 "
- }, {
- "$id": "43",
- "Code": "B",
- "Value": "错</p><p class=\"p3\">"
- }],
- "Answer": ["A"],
- "Explain": "</p><p class=\"p7\">有理数中,负数小于0,零小于正数,所以最小的是-3.</p><p class=\"p7\">备考指导:有理数大小比较的一般方法:①正数都大于0,负数都小于0,正数大于一切负数,两个负数绝对值大的反而小;②在数轴上表示的数,右边的总比左边的大.</p><p class=\"p6\">",
- "Type": "Judge"
- },
- {
- "$id": "44",
- "Question": "把a2-2a分解因式为a(a+2)。 ( )</p><p class=\"p7\">",
- "dif":"1",
- "Option": [{
- "$id": "45",
- "Code": "A",
- "Value": "对 "
- }, {
- "$id": "46",
- "Code": "B",
- "Value": "错</p><p class=\"p3\">"
- }],
- "Answer": ["B"],
- "Explain": "</p><p class=\"p7\">考查提取公因式法分解因式.原式=a(a-2).</p><p class=\"p7\">备考指导:因式分解的一般步骤:若有公因式,先提公因式;然后再考虑用公式法或其它方法分解;直到每个因式都不能再分解为止.</p><p class=\"p3\">",
- "Type": "Judge"
- },
- {
- "$id": "47",
- "Question": "一组数据3、8、12、17、40的中位数为12。()</p><p class=\"p7\">",
- "dif":"1",
- "Option": [{
- "$id": "48",
- "Code": "A",
- "Value": "对 "
- }, {
- "$id": "49",
- "Code": "B",
- "Value": "错</p><p class=\"p3\">"
- }],
- "Answer": ["A"],
- "Explain": "</p><p class=\"p7\">本题共5个数据,已经从小到大排列好,第3个数据12就是这组数据的中位数.</p><p class=\"p7\">备考指导:找中位数要把数据按从小到大的顺序排列,位于最中间的一个数(或两个数的平均数)为中位数,当数据个数为奇数时,即为中间的一个,当数据个数为偶数时,中位数就是中间两个数的平均数.</p><p class=\"p3\">",
- "Type": "Judge"
- },
- {
- "$id": "50",
- "Question": "火星白天的最高温度可达28℃,而夜间温度可降到-132℃,那么火星的昼夜温度相差<underline data=\"1\"><u> </u></underline>℃.</p><p class=\"p3\">",
- "dif":"1",
- "Option": [],
- "Answer": ["160"],
- "Explain": "</p><p class=\"p7\">解:根据题意列式得:28-(-132)=160℃.</p><p class=\"p3\">",
- "Type": "Complete"
- },
- {
- "$id": "51",
- "Question": "沙河水库的水文资料记载,最高水位:43.5米,警戒水位:42.8米,平均水位:40.0米,最低水位:36.4,下表是该水库内水位变化情况记录(上周末的水位达到警戒水位)表中“+“表示比前一天水位上升.</p><table class=\"t1\"><tbody><tr class=\"r1\"><td class=\"td4\"><p class=\"p16\">星期</p></td><td class=\"td5\"><p class=\"p16\">一</p></td><td class=\"td5\"><p class=\"p16\">二</p></td><td class=\"td5\"><p class=\"p16\">三</p></td><td class=\"td5\"><p class=\"p16\">四</p></td><td class=\"td5\"><p class=\"p16\">五</p></td><td class=\"td5\"><p class=\"p16\">六</p></td><td class=\"td5\"><p class=\"p16\">日</p></td></tr><tr class=\"r1\"><td class=\"td4\"><p class=\"p16\">水位变化/米</p></td><td class=\"td5\"><p class=\"p16\">-0.11</p></td><td class=\"td5\"><p class=\"p16\">+0.25</p></td><td class=\"td5\"><p class=\"p16\">-0.12</p></td><td class=\"td5\"><p class=\"p16\">-0.08</p></td><td class=\"td5\"><p class=\"p16\">-0.21</p></td><td class=\"td5\"><p class=\"p16\">+0.15</p></td><td class=\"td5\"><p class=\"p16\">+0.12</p></td></tr></tbody></table><p class=\"p17\">本周星期<underline data=\"1\"><u> </u></underline>水位最高,与警戒水位的距离是<underline data=\"2\"><u> </u></underline>米;最低水位是星期<underline data=\"3\"><u> </u></underline>,与警戒水位的距离是<underline data=\"4\"><u> </u></underline>米;最高水位与最低水位相差<underline data=\"5\"><u> </u></underline>米,与上周末水位相比,本周末的水位升降情况是<underline data=\"6\"><u> </u></underline>. </p><p class=\"p3\">",
- "dif":"5",
- "Option": [],
- "Answer": ["二", "0.14", "五", "0.27", "0.41", "不变"],
- "Explain": "</p><p class=\"p3\">解:星期一水位:42.8-0.11=42.69米,<br>星期二水位:42.69+0.25=42.94米,<br>星期三水位:42.94-0.12=42.82米,<br>星期四水位:42.82-0.08=42.74米,<br>星期五水位:42.74-0.21=42.53米,<br>星期六水位:42.53+0.15=42.68米,<br>星期日水位:42.68+0.12=42.80米,<br>所以,本周星期二水位最高,与警戒水位的距离是0.14米;<br>最低水位是星期五,与警戒水位的距离是0.27米;<br>最高水位与最低水位相差0.41米,<br>与上周末水位相比,本周末的水位升降情况是不变.<br>故答案为:二,0.14;五,0.27;0.41;不变.</p><p class=\"p3\">",
- "Type": "Complete"
- },
- {
- "$id": "52",
- "Question": "阜宁县各中小学校在新学年强势推进“双语阅读”工作.某校图书馆平均每天借书90册,如果某天借书95册,就记作+5;如果某天借书88册,就记作-2.上星期图书馆借出图书记录如下表:</p><table class=\"t1\"><tbody><tr class=\"r1\"><td class=\"td6\"><p class=\"p16\">星期一</p></td><td class=\"td7\"><p class=\"p16\">星期二</p></td><td class=\"td8\"><p class=\"p16\">星期三</p></td><td class=\"td8\"><p class=\"p16\">星期四</p></td><td class=\"td8\"><p class=\"p16\">星期五</p></td></tr><tr class=\"r1\"><td class=\"td6\"><p class=\"p16\">0</p></td><td class=\"td7\"><p class=\"p16\">+7</p></td><td class=\"td8\"><p class=\"p16\">+9</p></td><td class=\"td8\"><p class=\"p16\">-6</p></td><td class=\"td8\"><p class=\"p16\">-5</p></td></tr></tbody></table><p class=\"p18\">(1)上星期五借出图书是多少册?<br>(2)上星期二比上星期五多借出图书多少册?<br>(3)上星期平均每天借出图书多少册?</p><p class=\"p3\">",
- "dif":"5",
- "Option": [],
- "Answer": ["解:(1)根据题意可得:借出书比90多就记为“+”,比90本少就记为“-”;则上星期五借出图书是90-5=85册;<br>(2)∵上星期二借出图书为90+7=97(册),上星期五借出图书为90-5=85(册),<br>∴上星期二比上星期五多借出图书为97-85=12册.<br>(3)∵上星期一共借出图书(90+0)+(90+7)+(90+9)+(90-6)+(90-5)=455(册),<br>∴平均借出图书为91册.</p><p class=\"p3\">"],
- "Explain": "</p><p class=\"p14\">无</p><p class=\"p6\">",
- "Type": "Subjective"
- }]
- }
- },
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